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g100num [7]
3 years ago
9

$48The cost, c, of a ham sandwich at a deli varies directly with the number of sandwiches, n. If c = $54 when n is 9, what is th

e cost of the sandwiches when n is 3?
$18
$21
$27
$48
Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

c=18

Step-by-step explanation:

54 divided by 9 is 6

6 times 3 is 18

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( − 1 . 15 ) ⋅ 3 . 2 <br> find the product and explain how you got it
Sveta_85 [38]

Answer: -3.68

Step-by-step explanation:

-1.15*3.2=

-1.15*3+(-1.15*0.2)=

-3.45+(-0.23)=

-3.45-0.23=-3.68

3 0
2 years ago
Which one has the exact same amount of coins as the one above?
dezoksy [38]

Answer:

its b

count them!

3 0
2 years ago
Read 2 more answers
Which two terms in (3+14) +27 could you add to get a multiple of ten? ​
Aleksandr-060686 [28]

Answer:

3 and 27

Step-by-step explanation:

<u>Step 1:  Determine which two terms we can use</u>

We have the following numbers to choose from:  3, 14, 27

Adding two numbers to get a multiple of ten means that the number that we come up with needs to be divisible by ten.  For example:  20, 30, 50, 100 are all multiples of ten.

In this example the only one that would add up to create a multiple of ten is 27 and 3 which would give us 30 which is a multiple of 10.

Answer: 3 and 27

8 0
2 years ago
Diamond deposited $300 in a savings account that has a 2% interest rate per
Alexxandr [17]

Answer:

After 1 year: $306

After 2 years: $312.12

Step-by-step explanation:

Use the formula 300 x 1.02^{t}

t = no of years

So, Deposit x interest rate^{years}

4 0
3 years ago
13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas
Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

5+5^{2}=30 (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

5^{1}+5^{2}+5^{3}+...+5^{x}>19000 (II)

Buscamos el valor de x que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000

19530>19000

El valor de x que satisface (II) es x=6.

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro x=6, el número de horas que pasaron son 5 horas (1 menos que el valor de x)

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0
3 years ago
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