Answer:
There are none.
Step-by-step explanation:
<u>No calculus involved:</u>
The line, in slope-intercept form, has equation 
, ie is always decreasing (easy to spot applying the definition)
Meanwhile, 
is always increasing over its domain.
At no point the tangent will be decreasing.
<u>Let's use calculus</u>
We are to solve the equation 
which has no real solutions.
10g^3 - 8g^2 + 5g - 14 + 10g^2 + 12g
its just a matter of combining like terms
10g^3 + 2g^2 + 17g - 14
1,2,3,5,6,10,15,30 because by looking at the number at the ones place, when it is 0 or an odd number, it could be divided by 2. When the places are added together and when it is divisible by 3, it is the factor of 3. Also, when there are 2 and 3 as a factor, it is also divisible by 6.
The sum of angles in a quadrilateral = 360 degrees.
Let the fourth angle be x:
Therefore: 60 + 95 + 150 + x = 360
305 + x = 360
x = 360 - 305
x = 55
Option B. I hope this helps.
