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Taya2010 [7]
3 years ago
12

The weight Wkg of a metal bar varies jointly

Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer:

d = \sqrt{\frac{216W}{35L} }

Step-by-step explanation:

Given that W varies jointly as L and d² then the equation relating them is

W = kLd² ← k is the constant of variation

To find k use the condition W = 140 when d = 4 and L = 54, thus

140 = k × 54 × 4² = 864k ( divide both sides by 864 )

\frac{140}{864} = k , that is

k = \frac{35}{216}

W = \frac{35}{216} Ld² ← equation of variation

Multiply both sides by 216

216W = 35Ld² ( divide both sides by 35L )

\frac{216W}{35L} = d² ( take the square root of both sides )

d = \sqrt{\frac{216W}{35L} }

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Answer:

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Step-by-step explanation:

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3 years ago
Help please and thanks! I'll award brainliest if you show your work as well :)
iren2701 [21]

Answer:

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Step-by-step explanation:

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Use the quadratic equation to find the roots

x=(-b±\sqrt{b^2-4ac})*\frac{1}{2a} (sorry for formatting, Brainly doesn't

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x=\frac{-9+\sqrt{9^2-4*1*90} }{2(1)}        and          x=\frac{-9-\sqrt{9^2-4*1*90} }{2(1)}

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x=\frac{(-9+21)}{2}                   and          x=\frac{(-9-21)}{2}

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8 0
2 years ago
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bagirrra123 [75]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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3 years ago
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Answer:

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