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2 years ago

BRAINLY GET READY! I HAVE EXAMS NEXT WEEK! I WILL NEED HELP PLEASEEEE!!!. MATH BIOLOGY ELA CRIMINOLOGY!!!!!!

Mathematics

2 answers:

Alexxandr [17]2 years ago

8 0

Answer:

ready

Step-by-step explanation:

alekssr [168]2 years ago

4 0

Answer:

lol

Step-by-step explanation:

lol

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C) 175.84 cubic feet

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V=πr^2h is the formula I used

I plugged in the numbers and solved

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A pitcher holds 3 liters of lemonade. If the contents of the pitcher are equally divided among 8 people, how much lemonade will

igomit [66]

Answer:

0.375 litres

Step-by-step explanation:

Given that:

Total amount of lemonade held by pitcher = 3 litres

Number of people in which lemonade is to be given equally = 8

Amount of Lemonade received by each person will be:

Total amount of lemonade / number of persons

3 litres / 8

= 0.375 litres

Each person receives 0.375 litres of lemonade

8 0

2 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

BRAINLY GET READY! I HAVE EXAMS NEXT WEEK! I WILL NEED HELP PLEASEEEE!!!. MATH BIOLOGY ELA CRIMINOLOGY!!!!!!​

BRAINLY GET READY! I HAVE EXAMS NEXT WEEK! I WILL NEED HELP PLEASEEEE!!!. MATH BIOLOGY ELA CRIMINOLOGY!!!!!!