Answer:
yes, it is a right triangle and ∡Q is the right angle
Step-by-step explanation:
if the slope of QR is the opposite reciprocal of QS then the two segments are perpendicular and form a 90° angle
slope of QR: -3 - (-1) ÷ 2 - 0 = -2 ÷ 2 = -1
slope of QS: -3 - (-1) ÷ 2 - 4 = -2 ÷ -2 = 1
-1 and 1 are opposite and reciprocal so m∡Q = 90°
<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
Answer:
55
Step-by-step explanation:
difference=8-5=3
if difference is 3 Cole bends=5 times
if difference is 33 Cole bends=(5/3)×33=55 times
Answer:
see explanation
Step-by-step explanation:
h(x) + k(x) = x² + 1 + x - 2 = x² + x - 1
(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5
h(x) - k(x) = x² + 1 - (x - 2) = x² + 1 - x + 2 = x² -x + 3
(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9
h(2) = 2² + 1 = 4 + 1 = 5
k(3) = 3 - 2 = 1
3h(2) + 2k(3) = (3 × 5) + (2 × 1) = 15 + 2 = 17
