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NeTakaya
4 years ago
12

There are 5 times as many yellow labs as terriers in the dog park .if there are a total of 18 dogs how many dogs are terriers?

Mathematics
1 answer:
tekilochka [14]4 years ago
8 0
Let t = number of terriers
1 x t = number of total terriers
5 x t = number of yellow labs
1t + 5t = 6t
6t = total number of dogs in the park
6t = 18
t = 18/6
t = 3
there are 3 terriers
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b

Step-by-step explanation:

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3 years ago
On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?
bonufazy [111]

Answer:

Birds F_b=14.3\%

Gerbils F_g=42.9\%

Fish F_f=21.4\%

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Step-by-step explanation:

From the question we are told that:

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Number of birds  n_b=2

Number of gerbils  n_g=6

Number of fish  n_f=3

Number of hamsters  n_h=3  

Generally the frequency for birds F_b is mathematically given b

F_b=\frac{n_b}{n}*100

F_b=\frac{2}{14}*100

F_b=14.3\%

Generally the frequency for Gerbils F_g is mathematically given b

F_g=\frac{n_g}{n}*100

F_g=\frac{6}{14}*100

F_g=42.9\%

Generally the frequency for fish F_f is mathematically given b

F_f=\frac{n_f}{n}*100

F_f=\frac{3}{14}*100

F_f=21.4\%

Generally the frequency for fish F_h is mathematically given b

F_h=\frac{n_h}{n}*100

F_h=\frac{3}{14}*100

F_h=21.4\%

5 0
3 years ago
When a number is added to 1/5 of itself, the result is 24. The equation that models this problem is n +1/5 n = 24. What is the v
Lady_Fox [76]

For this case we must find the value of n of the following equation:

n + \frac {1} {5} n = 24

Taking common factor "n" from the left side of the equation we have:

n (1+ \frac {1} {5}) = 24\\n \frac {6} {5} = 24

Multiplying by 5 on both sides of the equation:

6n = 120

Dividing between 6 on both sides of the equation:

n = 20

Thus, the value of n is 20.

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n = 20

7 0
4 years ago
Read 2 more answers
Please help with number 11 please.
Tomtit [17]

Answer: 4/10

Step-by-step explanation:

2/5 = ?/10 As the amount of pieces correspond to the denominator

As 5x2 = 10

2x2 = 4

5 0
2 years ago
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