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klio [65]
3 years ago
11

Jim tried 2 basketball shots. If the probability of making a shot is 3/4, what is the probability of making both shots?

Mathematics
2 answers:
Travka [436]3 years ago
5 0

The probability of making the first shot is 3/4 .

The probability of making the second shot is 3/4 .

The probability of making both shots is (3/4) x (3/4) = <em>9/16</em> = 56.25 %


nadya68 [22]3 years ago
3 0
1 whole i believe. Hoped that helped

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3 years ago
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6 0
3 years ago
In a school election, Juan received 4 times as many votes as Wayne, Neal recurved twenty less votes than Juan, and Kerry got hal
77julia77 [94]

Votes received by Wayne is 112

<em><u>Solution:</u></em>

To find: votes received by Wayne

Let the vote received by Wayne be "x"

<em><u>Juan received 4 times as many votes as Wayne</u></em>

Therefore,

Juan votes = 4 times as many votes as Wayne

Juan votes = 4x  ---- eqn 1

<em><u>Neal received twenty less votes than Juan</u></em>

Neal votes = twenty less votes than Juan

Neal votes = Juan votes - 20

Neal votes = 4x - 20 ---- eqn 2

<em><u>Kerry got half as many votes as Neal</u></em>

Kerry votes = half of neal votes

Kerry votes = \frac{4x - 20}{2}  ---- eqn 3

The total votes cast in the election was 1,202

Wayne votes + Juan votes + Neal votes + Kerry votes = 1202

Plug in eqn 1 , eqn 2, eqn 3

x + 4x + 4x - 20 + \frac{(4x - 20)}{2} = 1202\\\\2x + 8x + 8x - 40 + 4x - 20 = 1202 \times 2\\\\22x - 60 = 2404\\\\22x = 2404 + 60\\\\22x = 2464\\\\x = 112

Therefore votes received by Wayne is 112

4 0
3 years ago
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Answer:

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7 0
3 years ago
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