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2 years ago

F(x)=x-2, find the following

Mathematics

1 answer:

grin007 [14]2 years ago

4 0

Answer:

Find the following what?

Step-by-step explanation:

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4/x-7=7/x+6<br><br> What is x

marissa [1.9K]

Answer:

Step-by-step explanation:

$4x + 24 = 7x - 49 \\ then \: collect \: the \: same \: variable \\ 4x - 7x = - 49 - 24 \\ x = - 63 \div - 3 = 21$

6 0

3 years ago

A cylinder has a radius of 3 cm. Sand is poured into the cylinder to form a layer 2 cm deep. What is the volume of sand in the c

netineya [11]

Answer:

Volume=56.54cm³

Step-by-step explanation:

$Solution,\\\\Radius(r)=3cm\\\\Height(h)=2cm\\\\Now,\\\\Volume=\pi r^{2} h\\\\Volume=\pi *(3cm)^{2} *2cm\\\\Volume=18\pi cm^{3} =56.54cm^{3}$

3 0

2 years ago

To win at LOTTO in one state, one must correctly select 4 numbers from a collection of 50 numbers (1 through 50). The order i

Oksana_A [137]

Answer:

230,300 different selections.

Step-by-step explanation:

If the order does not matter, the number of possible different selections is determined as the combination of choosing four numbers out of 50:

$n=\frac{50!}{(50-4)!4!}\\\\n=\frac{50*49*48*47}{4*3*2*1} \\\\n=230,300\ combinations$

There are 230,300 possible different selections.

4 0

2 years ago

Tell whether the relation is a function. {(-5, -3), (-1, 3), (4, 3), (8, 8)}

VladimirAG [237]

Given:

The relation is {(-5, -3), (-1, 3), (4,3), (8, 8)}.

To find:

Whether the given relation is a function or not.

Solution:

A relation is called a function, if there exist a unique output for each input.

We have, a relation given as

{(-5, -3), (-1, 3), (4,3), (8, 8)}

Here, all x-values are different. So, each x-value has a unique y-value.

Thus, there exist a unique output for each input.

Therefore, the given relation is a function.

8 0

3 years ago

Erin deposited $400 in a saving account earning 3% yearly compound interest. write an equation to represent how much money (y) E

bekas [8.4K]

$~~~~~~ \textit{Compound Interest Earned Amount \underline{in 15 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$400\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yeary, thus once} \end{array}\dotfill &1\\ t=years\dotfill &15 \end{cases}$

$A=400\left(1+\frac{0.03}{1}\right)^{1\cdot 15}\implies A=400(1.03)^{15}\implies A\approx 623.19 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=400(1.03)^x~\hfill$

4 0

2 years ago