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svp [43]
3 years ago
15

This may prove to be somewhat tricky.) Suppose that we have 10 coins, which are weighted so thatwhen flipped theith coin shows h

eads with probabilityp=i/10 (i= 1, . . . ,10). You randomly pick onecoin, you flip it, and it shows heads.Withoutputting this coin back, you pick a second coin. What is theprobability that the second coin shows heads, given that the first coin showed heads?
Mathematics
1 answer:
timama [110]3 years ago
4 0

Answer:

2/10

Step-by-step explanation:

Probability of getting head on i'th coin = i/10

Probability Pr of getting head on 2nd coin (Event A) = 2 / 10

Probability Pr of getting head on 1st coin (Event B) = 1/10

Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;

where A∩B = Pr (A & B) = Pr A X Pr B

Putting in above formula :

Pr (A/B) = <u>[(</u>1/10)x(2/10<u>)]</u>  / 1/10

= 2/10

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NARA [144]

Answer:

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Step-by-step explanation:

if your brother gives you 25 cents per day, at the end of 10 days you will have $2.50

if he gives you 1 cent per day then doubles it, this will be your daily earnings:

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