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3 years ago

Write the first 5 terms of the sequence 90 - 8n

Mathematics

1 answer:

Blababa [14]3 years ago

4 0

I hope this helps you

90-8.5

90-40

50

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Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he’ll call her on the

Ivenika [448]

Answer:

84%

Step-by-step explanation:

The probability of Thomas bumping into her at school is 80%, so the probability of not bumping into her is 100% - 80% = 20%.

If he doesn't bump into her (20% chance), he will call her, and the probability of asking her in this case is 60%, so the final probability of asking her in this case is:

$P_1 = 20\% * 60\% = 12\%$

If he bumps into her (80% chance), the probability of asking her is 90%, so the final probability of asking her in this case is:

$P_2 = 80\% * 90\% = 72\%$

To find the probability of Thomas inviting Madeline to the party, we just have to sum the probabilities we found above:

$P = P_1 + P_2$

$P = 12\% + 72\% = 84\%$

5 0

4 years ago

What is 25% of $4007

Nikitich [7]

Answer:

$1001.75

Step-by-step explanation:

Do 4007 x 0. 25 on a calculator

7 0

3 years ago

If f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (f * g) (x)

nadezda [96]

f(x) = 3x + 2 and g(x) = x² <span>+ 1
</span>⇒(f * g) (x) = ( 3x + 2 ) × ( x² + 1 )
= 3x³ + 2x² + 3x +2

3 0

3 years ago

Two square roots of 25/4

GarryVolchara [31]

$\sqrt{ \frac{25}{4} }=\frac{\sqrt{25}}{\sqrt{4}}=\frac{5}{2} 
$
AND
$\sqrt{ \frac{25}{4} }=\frac{\sqrt{25}}{\sqrt{4}}=\frac{-5}{-2}$

6 0

3 years ago

If the scientist is accurate, what is the probability that the proportion of airborne viruses in a sample of 477 viruses would d

melisa1 [442]

Answer:

0.01596

Step-by-step explanation:

A scientist claims that 8% of the viruses are airborne

Given that:

The population proportion p = 8%

The sample size = 477

We can calculate the standard deviation of the population proportion by using the formula:

$\sigma_p = \sqrt{\dfrac{p(1-p)}{n}}$

$\sigma_p = \sqrt{\dfrac{0.8(1-0.8)}{477}}$

$\sigma_p = \sqrt{\dfrac{0.0736}{477}}$

$\sigma_p = 0.02098$

The required probability can be calculated as:

$P(| \hat p - p| > 0.03) = P(\hat p - p< -0.03 \ or \ \hat p - p > 0.03)$

$= P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} < -\dfrac{0.03}{0.0124} \bigg ) + P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} >\dfrac{0.03}{0.0124} \bigg )$

= P(Z < -2.41) + P(Z > 2.41)

= P(Z < -2.41) + P(Z < -2.41)

= 2P( Z< - 2.41)

From the Z-tables;

$P(| \hat p - p| > 0.03)$ = 2 ( 0.00798

$P(| \hat p - p| > 0.03)$ = 0.01596

Thus, the required probability = 0.01596

3 0

4 years ago