If these are separated like:
<u>(6+8)*x, 4x+4+21, 4(2x+3), 6x+8x, 16(x+y+z), 8x+4+31, 4(x+2),</u> and <u>6x+6y+6</u><u>z</u>...
<em>Then it will be (6+8)*x with 6x+8x, 4x+4+21 with 8x+4+31, 4(2x+3) with 4(x+2), and 16(x+y+z) with 6x+6y+6z.</em><em> </em>Due to like terms, it only makes the most amount of sense.
What's bolded is your answer.
B because I did it on imagine math n it was right
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Solve for </u><em><u>y</u></em>
- Cross-multiply:

- Multiply:

- Isolate <em>y</em>:

- Rewrite:

<u>Step 3: Check</u>
<em>Plug in y to verify it's a solution.</em>
- Substitute:

- Divide:

Here, we see that 3.125 does indeed equal 3.125. ∴ y = 1.44 is a solution of the equation.
Answer:
6
Step-by-step explanation:
6+(6+2)+(6×3)=32
32÷(1+1+3)=6•••••2
So it's 6 and 6+2 and 6 times 3
which is 5 of number 6 plus 2
=6+(6+2)+(6×3)
=6+8+18
=32