Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
2 1/2 hours
Step-by-step explanation:
Divide 100 by 40 and you get 2.5
Night 1-
Wren 12
Jenni 4
Night 2-
Wren 16
Jenni 9
Night 3-
Wren 20
Jenni 14
Night 4-
Wren 24
Jenni 19
Night 5-
Wren 28
Jenni 24
Night 6-
Wren 32
Jenni 29
Night 7-
Wren 36
Jenni 34
Night 8-
Wren 40
Jenni 39
Night 9-
Wren 44
Jenni 44
It would be 9 nights.
Graph using (x) and (y), Wren being (x) and Jenni being (y)
Answer:
yes; 1.25
Step-by-step explanation:
The length to width ratios of the rectangles are ...
A: 12/8 = 1.5
B: 15/10 = 1.5
C: 30/15 = 2.0
__
Rectangles A and B have the same aspect ratio, so are similar. Rectangle B is a scaled copy of A with a scale factor of 10/8 = 1.25.
Answer:
11. 78
12. 4x² - 3x - 1
Step-by-step explanation:
11. Sum of n whole numbers = ½(n² + n)
Multiply
½*n² + ½*n
= n²/2 + n/2
To find the sum of the first 12 whole number, substitute 12 for n into the equation.
= 12²/2 + 12/2
= 144/2 + 12/2
= 72 + 6
= 78
12. Area of trapezoid = ½(a + b)*h
Where,
a = 5x - 4
b = 3x + 2
h = x + 1
Area = ½(5x - 4 + 3x + 2)*(x + 1)
Area = ½(8x - 2)*(x + 1)
Area = ½[8x(x + 1) -2(x + 1)]
= ½[8x² + 8x - 2x - 2]
Add like terms
= ½(8x² - 6x - 2)
= ½(8x²) - ½(6x) - ½(2)
= 4x² - 3x - 1
