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8090 [49]
3 years ago
12

How do i show my daughter how to do 17 × 9

Mathematics
1 answer:
satela [25.4K]3 years ago
3 0
17*9=17*10-17=170-17=153
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When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
I’ll give brainliest to whoever can do this
tino4ka555 [31]

i forgot hiw to do that

Step-by-step explanation:

8 0
3 years ago
. Given that O is the centre of the following circle, find the values of the unknowns.​
alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

a^{2} + 5^{2} = 13^{2}

a^{2} + 25 = 169

a^{2} = 169 - 25

a^{2} = 144

\sqrt{a^{2}}=\sqrt{144}

a = 12

Now to find the value of 'b', i will use law of cosine,

c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }

12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta =   0.3846\\\beta  = cos^{-1}(0.3846)\\\beta = 67.38

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

3 0
3 years ago
URGENT PLEASE HELP
TiliK225 [7]

a) The answer will be 456976 because you multiply 26 and 4.

b) The answer will be 358800 bacause you multiply 26*25*24*23

4 0
3 years ago
In 4 hours, the temperature steadily fell from 0°F to −12°F. What was the average change in temperature per hour? The average ch
grin007 [14]
-3 because it reduced -3 every hour of you divide -12 by 4 you will get -3 which is the average
4 0
3 years ago
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