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ladessa [460]
3 years ago
13

If an orange traffic cone has a diameter of 10 in. and a height of 28 in. what is the volume of the cone?

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

\large\boxed{V=\dfrac{700\pi}{3}\ in^3\approx732.67\ in^3}

Step-by-step explanation:

The formula of a volume of a cone:

V=\dfrac{1}{3}\pi r^2H

<em>r</em><em> - radius</em>

<em>H</em><em> - height</em>

We have the diameter <em>2r = 10in → r = 5in</em>, and the height <em>H = 28in.</em>

Substitute:

V=\dfrac{1}{3}\pi(5^2)(28)=\dfrac{1}{3}\pi(25)(28)=\dfrac{700\pi}{3}\ in^3

\pi\approx3.14\to V\approx\dfrac{(700)(3.14)}{3}\approx732.67\ in^3

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The y-intercept represents the initial money that Jana has in his account. Step-by-step explanation: Given the equation of line is . Also, Jana earns $ per week. And is the number of weeks she has been working. If we plug week in the equation . It will give us the y-intercept. That means the amount of money in Jana's account before she began mowing lawns. The y-intercept represents the initial money that Jana has in his account.  

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What are the domain and range of f (x) = log (x minus 1) 2?.
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You can use the definition of logarithm and the fact that a positive number raised to any power will always stay bigger than 0.

The domain of the given function is  {x | x > 1 and a real number }

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<h3>What is the definition of logarithm?</h3>

If a is raised to power b is resulted as c, then we can rewrite it that b equals to the logarithm of c with base a.

Or, symbolically:

a^b =  c \implies b = log_a(c)

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<h3>How to use this definition to find the domain and range of given function?</h3>

Since log(x-1) is with base 10 (when base of log isn't specified, it is assumed to be with base 10) (when log is written ln, it is log with base e =2.71828.... ) thus, we have a = 10 > 0 thus the input x-1 > 0 too.

Or we have:

x > 1 as the restriction.

Thus domain of the given function is {x | x > 1 and a real number }

Now from domain, we have:

x >  1\\&#10;x-1 > 0\\&#10;log(x-1) > -\infty\\&#10;log(x-1) + 2 > -\infty\\&#10;f(x) > -\infty (log(x-1) > -infinity since log(0) on right side have arbitrary negatively large value which is denoted by -infinity)

Thus, range of given function  is whole real number set \mathbb R (since all finite real numbers are bigger than negative infinity)

Thus, the domain of the given function is  {x | x > 1 and a real number }

The range of the given function is \mathbb R (set of real numbers

Learn more about domain and range here:

brainly.com/question/12208715

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