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marin [14]
3 years ago
14

John is about to roll a six sided, fair number cube 60

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

No it is not a good prediction. Theoretical probability says that the answer would be 30 of the 60 (30/60) rolls would be even numbers.

Step-by-step explanation:

The probability of rolling an even number on a fair six sided die is 3/6 or 1/2 when simplified.

if john rolls the die 60 times, multiply the theoretical probability (1/2) by the number of rolls

(1 ÷ 2) x 60 = 30

∴ theoretical probability says that john would roll an even number 30 out of the 60 rolls

I hope this was helpful :-)

vagabundo [1.1K]3 years ago
5 0

Answer:

A number cube has 3 even numbers. Each even number has a theoretical probability of 1/6. In 60 rolls, an even number could come up ten times. Since there are 3 even numbers, the total predicted value is 30. So 20 is a low prediction.

._.

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Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

40,\:10,\:\frac{5}{2},\:\frac{5}{8}

A geometric sequence has a constant ratio 'r' and is defined by

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\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}

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r=\frac{1}{4}

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

a_1=40

Therefore, the nth term is calculated as

\:a_n=a_0\cdot r^{n-1}

a_n=40\left(\frac{1}{4}\right)^{n-1}

Put n = 5 to find the next term

a_5=40\left(\frac{1}{4}\right)^{5-1}

a_5=40\cdot \frac{1}{4^4}

a_5=\frac{40}{4^4}

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a_5=\frac{5}{2^5}

a_5=\frac{5}{32}

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a_6=40\left(\frac{1}{4}\right)^{6-1}

a_6=40\cdot \frac{1}{4^5}

a_6=\frac{40}{4^5}

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a_6=\frac{5}{2^7}

a_6=\frac{5}{128}

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

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