The first step is to determine the distance between the points, (1,1) and (7,9)
We would find this distance by applying the formula shown below
![\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20%5C%5C%20%5Ctext%7BFrom%20the%20graph%2C%20%7D%20%5C%5C%20x1%5Ctext%7B%20%3D%201%2C%20y1%20%3D%201%7D%20%5C%5C%20x2%5Ctext%7B%20%3D%207%2C%20y2%20%3D%209%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%287-1%29%5E2%2B%289-1%29%5E2%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B6%5E2%2B8%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%2010%7D%20%5Cend%7Bgathered%7D)
Distance = 10 units
If one unit is 70 meters, then the distance between both entrances is
70 * 10 = 700 meters
Drawing it out, as seen, using the Pythagorean theorem we get that w^2+l^2 (with w=width and l=length)=diagonal^2=24^2+l^2=40^2. Subtracting 24^2 from both sides, we get 40^2-24^2=l^2=1024. Square rooting both sides, we get l=32. Since the perimeter is 2w+2l, we get 32*2+24*2=64+48=112
A geometric series like
Converges if and only if 
. If this is the case, the sum equals
So, in your case, you have convergence if and only if
And if this is the case, the sum equals
<h3>
Answer:</h3>
x = -5/2
<h3>Explanation:</h3>
<u>Given</u>
(2x+1)/(x-2) + 4/x= -8/(x^2-2x)
<u>Find</u>
x
<u>Solution</u>
We note that the denominators in this equation are x and x-2. The solution set must exclude these values, as the equation is "undefined" for those values of x.
__
Multiply by x(x-2)
x(2x+1) +4(x-2) = -8
2x² +5x = 0 . . . . . . . . . . add 8, eliminate parentheses
x(2x +5) = 0
The solutions are the values of x that make these factors zero:
x = 0 . . . . must be excluded
x = -5/2
The solution to the equation is x = -5/2.
