All categories

3 years ago

A recipe requires 1/4 lb of onions to make 3 servings of soup mark has 1.5 lbs of onions how amy sevings can mark make

Mathematics

1 answer:

Flura [38]3 years ago

5 0

Sounds like 18 servings to me.

6 quarters go into 1.5

6 x 3 is 18 so 18 servings.

You might be interested in

60 What is the sum of the series E3n?

wariber [46]

Answer:

B, 2,010

Hope this helps have a nice day/night :)

6 0

3 years ago

Read 2 more answers

HELP !! im going to post a picture of this math problem . i need an answer and explanation asap ..

Diano4ka-milaya [45]

The 3rd one is the correct answer

3 0

3 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

Step 2: Find Right-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

Step 3: Find Left-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ Since $\displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)$ , then $\displaystyle \lim_{x \to 5} f(x) = DNE$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

2 years ago

Not rlly a paper I gotta do buuuut, say I have seven one hundreds, one ninety nine, and two zeros... what would my grade be in t

vlabodo [156]

If they’re all weighted equally, then your average grade will be 79.9%

8 0

3 years ago

If 10,500 is decomposed in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y

Irina-Kira [14]

1) To work out the result after a percentage is applied to a number, you work out 'the percentage number/100' and write the answer of this calculation down. 2) You THEN multiply this calculated number (called the 'percentage multiplier') by your orginal number (called the 'principal'). 3) The result of this calculation gives you the answer of what happens when your orginal number is multiplied by a certain percentage. 4) Thus, for a 2.99% increase work out: " (100+2.99)/100 "
The answer is 1.029 - SO THIS is your percentage multiplier. 5) Your earn 2.99% interest each year for 5 years. Thus you multiply your principal (10,500) by the calculated percentage multiplier (1.029), BUT you you multiply the principal by this multiplier 5 TIMES! 6) So, the calulation is:10,500 × (1.029^5). 7) This EQUALS $12,113.403198) Rounded to the nearest cent, the final amount in the account AFTER 5 YEARS = $12,113.40 8) THE ANSWER IS THUS: $12,113.40

8 0

3 years ago