What should you do to both sides to solve the following equation? t 15 t15 + 10 = 14 Subtract 14 then multiply by 15 Subtract 15
then multiply by 10 Subtract 10 then multiply by 15 Subtract 14 then multiply by 10
1 answer:
Answer:
substract 10 and multiply 10
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2(3)^2+(4)^3-12
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18+52
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1.BD=AC
AC^2=(9^2)+(6^2)-2(9)(6)COS115
AC^2=117-108COS115
AC=√71.358
AC=8.447//
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