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Juli2301 [7.4K]
4 years ago
10

What is the y-intercept of the function f(x)=4-5x​

Mathematics
1 answer:
NISA [10]4 years ago
8 0

Answer:

x-(4/5,0) y-(0,4)

Step-by-step explanation:

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I cannot see the question clearly. But I know how to do .

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Which of the following is the quotient of the rational expression (x-2/x+3) divided by (2/x)
zloy xaker [14]

Answer:

(x²-2x)/(2x+6)

Step-by-step explanation:

When you are asked to divide two fractions just do keep-change-flip. Keep the first fraction, change the ÷ to x and flip the second fraction upside down. So the problem becomes ((x-2)/(x+3)) times (x/2). Then just multiply numerators and multiply denominators.

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How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
Does anyone know ? what is the value of k
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Good answer is -1:) have a good day;)

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c

The domain of the function is all real numbers greater than or equal to 0.

The range of the function is all real numbers greater than or equal to −1.

The range of the function is all real numbers less than or equal to 0.

The domain of the function is all real numbers less than or equal to 0

7 0
2 years ago
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