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3 years ago

Write an equation of the line that passes through (3,2) and is perpendicular to the line y=1/3x-3

Mathematics

1 answer:

Tasya [4]3 years ago

4 0

Answer:

y=-3x+11 ?

Step-by-step explanation:

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Find the 10th term of the geometric sequence whose common ratio is 3/2 and whose first term is 8

igor_vitrenko [27]

Answer: 19683/64

Step-by-step explanation:

$a_{n}=8\left(\frac{3}{2} \right)^{n-1}\\\\\implies a_{10}=8 \left(\frac{3}{2} \right)^{10-1}=\boxed{\frac{19683}{64}}$

3 0

2 years ago

Refer to image below

il63 [147K]

Answer:

A ≈ 40°

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] sinθ = opposite over hypotenuse

Step-by-step explanation:

Step 1: Identify

Angle θ = A

Opposite Leg = 27

Hypotenuse = 42

Step 2: Solve for A

Substitute [sine]: sinA = 27/42
Simplify: sinA = 9/14
Trig inverse: A = sin⁻¹(9/14)
Evaluate: A = 40.0052°
Round: A ≈ 40°

5 0

3 years ago

3 and 7/10 x 4 and 4/5 Please help I want to now if my answer is correct

BabaBlast [244]

The answer is 17 and 19/25

3 0

3 years ago

How do i do this question?

zysi [14]

The length of BC = 72

Solution:

Given ΔABC and ΔDEF are similar triangles.

ΔABC $\sim$ ΔDEF

AB = 54, BC = n, EF = 12, DE = 9

Similar triangle theorem:

If two triangles are similar then the corresponding sides are proportional to each other.

$$\Rightarrow\frac{BC}{EF}=\frac{AB}{DE}$

Substitute the given values, we get

$$\Rightarrow\frac{n}{12}=\frac{54}{9}$

Do cross multiplication.

$$\Rightarrow9\times n=54\times12$

Divide both sides of the equation by 9.

$$\Rightarrow n=\frac{54\times12}{9}$

$$\Rightarrow n=6\times12$

$$\Rightarrow n=72$

⇒ BC = 72

Option B is the correct answer.

The length of BC = 72.

4 0

4 years ago

The bottom of a double rainbow is going over a tree that is 18 feet tall if you're standing 20 feet from the tree what is the an

ivanzaharov [21]

The angle of elevation to the bottom of the rainbow is 42°

Explanation:

Given that the bottom of a double rainbow is going over a tree that is 18 feet tall and you're standing 20 feet from the tree.

We need to determine the angle of elevation to the bottom of the rainbow.

Let us use the trigonometric ratios to determine the angle of elevation.

Thus, we have,

$tan \ \theta=\frac{opp}{adj}$

where opp = 18 and adj = 20 and we need to determine the angle.

Substituting the values, we have,

$tan \ \theta=\frac{18}{20}$

Dividing the values, we have,

$tan \ \theta=0.9$

Taking $tan^{-1$ on both sides of the equation, we get,

$\theta=tan^{-1}(0.9)$

Thus, we get,

$\theta=41.99^{\circ}$

Rounding off to the nearest degree, we get,

$\theta=42^{\circ}$

Hence, the angle of elevation to the bottom of the rainbow is 42°

6 0

3 years ago