




//
If the 3 is an exponent, then the person above me is right.
<em><u>a</u></em><em><u> </u></em><em><u>highway</u></em><em><u> </u></em><em><u>measures</u></em><em><u> </u></em><em><u>5</u></em><em><u>8</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>miles</u></em><em><u> </u></em><em><u>long</u></em><em><u>.</u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>speed</u></em><em><u> </u></em><em><u>limit</u></em><em><u> </u></em><em><u>sign</u></em><em><u> </u></em><em><u>posted</u></em><em><u> </u></em><em><u>every</u></em><em><u> </u></em><em><u>two</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>six</u></em><em><u> </u></em><em><u>miles.How</u></em><em><u> </u></em><em><u>many</u></em><em><u> </u></em><em><u>speed</u></em><em><u> </u></em><em><u>limit</u></em><em><u> </u></em><em><u>signs</u></em><em><u> </u></em><em><u>Will </u></em><em><u>be</u></em><em><u> </u></em><em><u>on</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>highway</u></em><em><u> </u></em>
<em><u>(</u></em><em><u>C</u></em><em><u>)</u></em><em><u>:</u></em><em><u>2</u></em><em><u>9</u></em><em><u> </u></em><em><u>.</u></em><em><u>signs</u></em>
Answer:

Step-by-step explanation:
Given



Required
The volume of the remaining cylinder
Before the cut-out, the cylinder has a volume (V) of:

After the cut-out, the cylinder has a volume of:
![V = \pi [R^2 -r^2]h](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%5BR%5E2%20-r%5E2%5Dh)
So, we have:
![V = 3.14* [6^2 -5^2]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B6%5E2%20-5%5E2%5D%2A15)
![V = 3.14* [36 -25]*15](https://tex.z-dn.net/?f=V%20%3D%203.14%2A%20%5B36%20-25%5D%2A15)


Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So



has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Substitute X or Y With 0 So It Would Be 3/5(0) +1/2y = 30
1/2y=30
Divide Get Y And Do The Same For X