Question

How are these two equations related? (x^2-1)/(x+1)= x-1 and x^2-1=(x+1)(x-1)

Answer 1

Answer:

These two equations are related to each other by identity $a^2-b^2=(a+b)(a-b)$  

Step-by-step explanation:

We have given equations

$\frac{x^2-1}{x+1}$

We know the algebraic identity

$a^2-b^2=(a+b)(a-b)$

So $a^2-1^2=(x+1)(x-1)$

So $\frac{x^2-1}{x+1}=\frac{(x+1)(x-1)}{x+1}=(x-1)$

So these two equations are related to each other by algebraic identity $a^2-b^2=(a+b)(a-b)$