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koban [17]
3 years ago
5

How are these two equations related? (x^2-1)/(x+1)= x-1 and x^2-1=(x+1)(x-1)

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

These two equations are related to each other by identity a^2-b^2=(a+b)(a-b)  

Step-by-step explanation:

We have given equations

\frac{x^2-1}{x+1}

We know the algebraic identity

a^2-b^2=(a+b)(a-b)

So a^2-1^2=(x+1)(x-1)

So \frac{x^2-1}{x+1}=\frac{(x+1)(x-1)}{x+1}=(x-1)

So these two equations are related to each other by algebraic identity a^2-b^2=(a+b)(a-b)

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