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4 years ago

Please answer quickly!!!

Mathematics

1 answer:

mixas84 [53]4 years ago

3 0

Answer:

Step-by-step explanation:

5x + 13y = 232

12x + 7y = 218

For each choice:

a) The first equation can be multiplied by –13 and the second equation by 7 to eliminate y. So we have

- 65x - 169y = - 3016

84x + 49y = 1526

Can not eliminate x and y.

b) The first equation can be multiplied by 7 and the second equation by 13 to eliminate y. So we have

35x + 91 y = 1624

156x + 91y = 2834

Can not eliminate x and y if we ADD.

<em>(If we subtract, this is Yes)</em>

c) The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

-60x - 156y = - 2784

60x + 35y = 1090

The answer is YES

d) The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.

25x + 65y = 1160

144x + 84y = 2616

Can not eliminate x and y

The final answer is C

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In a recent survey, 64 % of the community favored building a police substation in their neighborhood. If 14 citizens are chosen,

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Answer: 0.1840

Step-by-step explanation:

The binomial probability formula :-

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$P(8)={14}^C_{8}\ (0.64)^{8}(1-0.64)^{14-8}\\\\=\dfrac{14!}{8!6!}\times(0.64)^8(0.36)^{6}\\\\0.183996740126\approx0.1840$

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4 years ago

Find the LCM of k^2 + 3k + 2 and 2k^2 + 14k + 20.

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Answer:

C. 2(k +2)(k +5)(k +1)

Step-by-step explanation:

The LCM will be the product of unique factors.

$(k^2 + 3k + 2)=(k+1)(k+2)\\(2k^2 + 14k + 20)=2(k+2)(k+5)$

The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:

2(k+1)(k+2)(k+5) . . . . matches choice C

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3 years ago