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2 years ago

Can someone help me pls :)

Mathematics

2 answers:

Sergeeva-Olga [200]2 years ago

7 0

Answer:

Step-by-step explanation:

AREA = L * W

SO W= A / L

guajiro [1.7K]2 years ago

6 0

Answer:A or D

Step-by-step explanation:

Length times width equals area so

Area divided by length equals width

50 dived by 25 equals 2

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A doctor at a local hospital is interested in estimating the birth weight of infants. How large a sample must she select if she

Nataly_w [17]

Answer:

The minimum sample size needed is $n = (\frac{1.96\sqrt{\sigma}}{4})^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean?

A sample of n is needed, and n is found when M = 4. So

$M = z\frac{\sigma}{\sqrt{n}}$

$4 = 1.96\frac{\sigma}{\sqrt{n}}$

$4\sqrt{n} = 1.96\sqrt{\sigma}$

$\sqrt{n} = \frac{1.96\sqrt{\sigma}}{4}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{\sigma}}{4})^2$

$n = (\frac{1.96\sqrt{\sigma}}{4})^2$

The minimum sample size needed is $n = (\frac{1.96\sqrt{\sigma}}{4})^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

4 0

2 years ago

Plz help<br> this is also timed and sorry that the screen looks like this:(

Galina-37 [17]

Answer:

2 hours, 15 minutes

Step-by-step explanation:

3:30 to 5:30 is 2 hours elapsed time.

5:30 to 5:45 is 15 minutes elapsed time.

2 hrs + 15 mins =2 hrs 15 mins.

6 0

2 years ago