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Sladkaya [172]
3 years ago
11

Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant

speed to get to the safe zone that was 160 meters away. After 3 seconds of driving, she was 85 meters away from the safe zone. Let D represent the distance (in meters) from the safe zone after t seconds. Complete the equation for the relationship between the distance and number of seconds. D=
Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

The answer is D(t) = 160 - 25t

Step-by-step explanation:

well khan academy said it lol

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If x2 +8x-4=x2+8, then 2x-3+?
DanielleElmas [232]

Answer: The number 0

x^2 + 8x - 4 = x^2 + 8

8x - 4 = 8 ... subtract x^2 from both sides

8x = 12 .... add 4 to both sides

x = 12/8 .... divide both sides by 8

x = 3/2 ... reduce

x = 1.5 .... convert to decimal form

Now plug x = 1.5 into the expression 2x-3 and simplify

2x-3 = 2*1.5-3 = 3-3 = 0 which is the answer

3 0
3 years ago
Find value of X (Show steps on how to solve)
zaharov [31]

Answer:

11°

Step-by-step explanation:

Here in the figure , angle(BAC) = angle(QSR) = 45°

also, angle(ABC) = angle(SQR) = 80°.

In triangle SQR,

angle(QSR) + angle(SQR) + angle(SRQ) = 180°

=> angle(SRQ) = 180 - ( 45 + 80 )

= 180 - 125

= 55°

But angle(SRQ) = 5x ( its given in question )

So,

5x = 55°

=> x = 11°

5 0
3 years ago
Pratap Puri rowed 14 miles down a river in 2 ​hours, but the return trip took him 3 and one half hours. Find the rate Pratap can
SOVA2 [1]

speed of current is 1.5 mi/hr

Answer:

let the rate in still water be x and rate of the current be y.

speed down the river is:

speed=distance/time

speed=14/2=7 mi/h

speed up the river is:

speed=(14)/(3.5)=4 mi/hr

thus total speed downstream and upstream will be:

x+y=7...i

x-y=4.......ii

adding the above equations i and ii we get:

2x=11

x=5.5 mi/hr

thus

y=5-5.5=1.5 mi/r

thus the speed in still waters is 5.5 mi/hr

speed of current is 1.5 mi/hr

7 0
2 years ago
What is the lateral area of the pyramid
Mkey [24]

Answer:

43.75 ft²

Step-by-step explanation:

s_l = (l√(w/2)² + h²) + (w√(l/2)² + h²)

l & w become 3.5, and h becomes 6.

<em />s_l<em> </em>= (3.5√(3.5/2)² + 6²) + (3.5√(3.5/2)² + 6²)

<em>Step 1:Because this is a square pyramid, what you see above essentially becomes what you see below.</em>

<em />s_l = 2(3.5√(3.5/2)² + 6²)

<em>Step 2: Divide 3.5 by 2 to get 1.75.</em>

<em />s_l<em> </em>= 2(3.5√1.75² + 6²)

<em>Step 3: Square both 1.75 and 6 to get 3.0625 and 36 respectively.</em>

s_l = 2(3.5√3.0625 + 36)

<em>Step 4: Add 3.0625 and 36 to get 39.0625.</em>

<em />s_l = 2(3.5√39.0625)

<em>Step 5: The square root of 39.0625 is 6.25.</em>

<em />s_l<em> </em>= 2(3.5 * 6.25)

<em>Step 6: Multiply 3.5 by 6.25 to get 21.875.</em>

<em />s_l = 2(21.875)

<em>Step 7: Multiply 2 by 21.875 to get 43.75.</em>

<em />s_l = 43.75 ft²

The lateral area of this pyramid is 43.75 ft².

<em />

<em />

3 0
2 years ago
Hey can I have some quick help please?<br> Is the answer I chose correct?
Gennadij [26K]

Answer:

Yes, I am 99% sure your right.

8 0
3 years ago
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