Question

I really need help asap

Answer 1

Answer:

$a=3,b=7,c=-20$

Step-by-step explanation:

we are given equation as

$3x^2=20-7x$

Firstly, we will move all terms on left side

Subtract both sides by 20

$3x^2-20=20-7x-20$

$3x^2-20=-7x$

Add both sides by 7x

$3x^2-20+7x=-7x+7x$

$3x^2-20+7x=0$

$3x^2+7x-20=0$

now, we can compare it with quadratic equation

$ax^2+bx+c=0$

and we get

$a=3,b=7,c=-20$