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musickatia [10]
3 years ago
9

Express in exponential form log2(x)=3

Mathematics
1 answer:
Nataly [62]3 years ago
4 0
Log_a b = x so than b = a^x

in this your case log2(x) = 3 => x = 2^3 so x = 8
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Write an equation of the line that passes through (3,1) and (0,10) .
frutty [35]

Answer:

(1,1) and (0,1)

Step-by-step explanation:

i think thats it i dont know what it looks like i need a picture of it

7 0
2 years ago
Kim ran a mile in PE class. After resting for 1 hour her heart rate was 75 beats per minute. If her heart rate decreased by ⅖ ,
Andreas93 [3]

Answer:

125

Step-by-step explanation:

since you take away 2/5 of the original number to get 75, 75 is equal to 3/5's of the original. You then divide 75 by 3, get 25, then multiply 25 by 5 to find the answer which is 125.

6 0
3 years ago
A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
2 years ago
I really really need help someone!! )):
yaroslaw [1]

diameter is 15 meters then radius is 15/2 = 7.5 meters

so the amplitude is 7.5 m and height will oscillate with amplitude 7.5 m above and below the center.

midline of the oscillation will be 7.5 m

the wheel.take 8 minutes to complete revolution then it means the height will oscillate with a period of 8 minutes

3 0
4 years ago
Which set of ordered pairs represents a function
11Alexandr11 [23.1K]

Answer:

C: is a function because each input (x) has exactly one output( y).

Step-by-step explanation:

A function is when one input (x) has exactly one output (y).

A: is not a function because -4 is paired with two different y values.

B: is not a function because -4 is paired with two different y values.

C: is a function because each input (x) has exactly one output( y).

D: is not a function because -1 is paired with two different y values.

3 0
2 years ago
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