THIS IS ALL MY POINTS
2 answers:
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Answer:
x =
Step-by-step explanation:
4x-y+2z = 8x+y-4
4x-8x-y+2z = 8x - 8x +y-4
-4x -y +2z= y-4
-4x -y+y +2z = y+y-4
-4x +2z = 2y-4
-4x+2z-2z = 2y-2z-4
-4x = 2y-2z-4
=
Answer:
a.
b.
c.
No, it is not unusual if at least 1 lives up to 3.
Step-by-step explanation:
Given
Represent the probability that a 2 year old snake will live to 3 with P(Live);
Solving (a): Probability that two selected will live to 3 years.
Both snakes have a chance of 0.98861 to live up to 3 years.
So, the required probability is:
<em>--- Approximated</em>
Solving (b): Probability that seven selected will live to 3 years.
All 7 snakes have a chance of 0.98861 to live up to 3 years.
So, the required probability is:
Where
<em>--- Approximated</em>
Solving (c): Probability that at least one of seven selected will not live to 3 years.
In probabilities, the following relationship exist:
So, first we need to calculate the probability that none of the 7 lived up to 3.
If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861
This gives:
The probability that none of the 7 lives up to 3 is:
Substitute this value for P(None) in
---- Approximated
No, it is not unusual if at least 1 lives up to 3.
This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years
Answer: for number 7
Step-by-step explanation:
a²+b²=c²
3²+8²=c²
9+64=c²