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brilliants [131]
2 years ago
14

Aliaa and Zhang Li are tennis-playing robots capable of placing shots with superhuman precision. Aliaa is about to hit its next

shot to the far corner of the court. It (Aliaa) knows that the distance between itself and Zhang Li is 520\,\text{cm} 520cm 520, start text, c, m, end text , and it knows that the angle between Zhang Li and the far corner is 53^\circ 53 ∘ 53, degrees . Similarly, Zhang Li knows that the angle between Aliaa and the far corner is 100^\circ 100 ∘ 100, degrees . What distance should Aliaa hit the ball so that it lands perfectly in the far corner of the court? Do not round during your calculations. Round your final answer to the nearest centimeter.
Mathematics
1 answer:
gtnhenbr [62]2 years ago
6 0

Answer:

1128 according to khan academy

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The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
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Answer:

a

    f'(t) is  negative

b

 The  unit is degC/min

c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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