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lana66690 [7]
4 years ago
14

An airplane has just enough fuel for a 6 hour flight. How far can it fly, roundtrip, in which during the first leg of the trip,

it flies with the wind at 235 miles per hour, and during the return trip, it flies against the wind at 190 miles per hour? Round to the nearest thousandth.
Mathematics
1 answer:
Jlenok [28]4 years ago
8 0
630.35 by using the equation 6=x/235+x/190
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Expedia would like to test the hypothesis that the average round-trip airfare between Philadelphia and Paris is higher for a fli
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Answer:

(b) 32

Step-by-step explanation:

From the information given :

sample mean of Philadelphia μ₁ = $1240

Sample size of Philadelphia n₁ = 15

Sample Standard deviation σ₁ = $270

sample mean of Paris μ₂ = $1,060

Sample size of Paris  n₂ = 19

Sample Standard deviation of Paris  σ₂ = $240

If Population 1 is defined as flights originating in Philadelphia and Population 2 is defined as flights originating in Paris;

the degrees of freedom for this hypothesis test can be calculated as;

degree of freedom df = n - 1

degree of freedom for both hypothesis test = (n₁ - 1 + n₂ -1)

degree of freedom for both hypothesis test  = (n₁ + n₂ - 2)

degree of freedom for both hypothesis test  = ( 15 + 19 - 2)

degree of freedom for both hypothesis test are <u>  </u><u> 32  </u><u> </u>

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How many cups of loam are needed to make 66c of potting soil?
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If a bag contains 12 apples, 4 bananas, and 8 oranges, what is the part-to-whole ratio bananas to all fruit
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6 0
4 years ago
Read 2 more answers
Question below
Ksivusya [100]

Answer:

m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]

Therefore:

\implies 3=\dfrac{2}{3}m

\implies m=3 \times \dfrac{3}{2}

\implies m=\dfrac{9}{2}

<u>Calculate the value of H</u>

Given:

\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)

Therefore:

\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />

<u>Calculating m × H</u>

<u />

<u />\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]

\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]<u />

7 0
2 years ago
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