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Virty [35]
3 years ago
6

Which of the following situations best models the materials needed to build the fence for the warehouse lot shown in the general

contractor’s design? The general contractor should purchase enough materials for approximately 3,000 linear feet of fencing. The general contractor should purchase enough materials for approximately 3,300 linear feet of fencing. The general contractor should purchase enough materials for 615,636 linear feet of fencing. None of the above.
Mathematics
1 answer:
Len [333]3 years ago
6 0
I can help if you somehow find a way to show me the warehouse lot or give me the info on it, if theres a picture or graph of it screenshot it and give it to me? then I can help~
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What is the distance between (4,5) and (-3,0)
Vladimir79 [104]

Answer:

You need to upload an image about the grid/graphic so I can answer that

Step-by-step explanation:

4 0
3 years ago
All of the students of Music High School are in the band, the orchestra, or both. 80 percent of the students are in only one gro
il63 [147K]

Answer:

Option B.

Step-by-step explanation:

It is given that all of the students of Music High School are in the band, the orchestra, or both.

Students only one group = 80%

Students in both groups = 100%-80% = 20%

Students in band only = 50%

Students in band = Students in band only + Students in both groups

                             = 50% + 20% = 70%

Students in orchestra only = 100% - 70% = 30%

There are 119 students in the band.

Let total number of student be x.

70\% of x=119

\dfrac{70}{100}x=119

0.7x=119

x=170

Total number of students is 170.

We know that 30% of all students are in orchestra only.

170\times \dfrac{30}{100}=51

Therefore, the correct option is B.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%3F%20191" id="TexFormula1" title="\sqrt? 191" alt="\sqrt? 191" align="absmiddle" class
OlgaM077 [116]
13.8203 i think if i’m wrong i’m so sorry
5 0
3 years ago
Situation:
Rzqust [24]
N=NOe^-kt
N=mass at time t
NO = initial mass
k= 0.1476
t= time, in days

We are asked to find the half-life, which means you want to find how long it will take for half of the substance to decay/disappear (depending on situation). 

If we are looking for half-life, we can simply set N to half of NO (which we are given a value of 40grams for)
Therefore:
N = 20
NO = 40
plugging these values and the value given for k back into the equation you get:

20 = 40e^-0.1476(t)
We are looking for t, so we have to manipulate the formula to get t by itself on one side of the equation.
We can start by dividing 40 from both sides, and you get:
0.5 = e^-0.1476(t)

We have the exponential function "e".
To get rid of e, we can use natural log (ln)
if e^y=x then ln (x) = y
look back at our equation we can set
0.5 = x
-0.1476(t) = y

Rewriting it in natural log form:
ln (0.5) = -0.1476(t)
Plug in ln (0.5) on a calculator to find its value and we get:
-0.693147 = -0.1476(t)
*Note: normally, getting a negative value would suggest that we did something wrong, because you cannot have a negative value as your t (you cannot have negative days), but because there is a negative on both sides of the equation, they will cancel out in this case. 

The last step is to simply divide both sides by -0.1476
therefore:
T = 4.696119
But it asks you for the answer to the nearest tenth (one place after decimal pt) so 
T (half life) = 4.7 days

Hope that helps :)
8 0
3 years ago
How do I work this out
alukav5142 [94]

9514 1404 393

Answer:

  no, it is good for 2 weeks (almost 3)

Step-by-step explanation:

The volume of the pool is ...

  V = LWH

  V = (20 m)(8 m)(1.8 m) = 288 m³

Then the amount of chlorine powder needed for 1 week is ...

  (300 g/(50 m³)) × (288 m³) = 1728 g

A box of 5000 g holds enough chlorine for ...

  (5000 g)/(1728 g/treatment) = 2.89 treatments

A box of chlorine powder is enough for 2 weeks, not 4.

5 0
3 years ago
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