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chubhunter [2.5K]
3 years ago
7

Which expressions are equivalent to 1 Over 36

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

6¯²

\frac{6^{3} }{6^{5} }

6^{-9}.6^{7}

its true i think

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Please help i'm so confused
umka21 [38]

Answer:

if it's bot raining, then it's sunny

8 0
3 years ago
Someone pls help me
Nat2105 [25]
The answer should be AC+BC

We can answer this by applying the rule called "Greater angle, greater side". This is where in any triangle, the opposite side of the larger angle is also longer.

So in this question, first we have to find the largest 2 angles, which is ∠ABC and ∠BAC with measures of 120° and 35° respectively. Therefore, from the diagram, the opposite sides of the angles are AC and BC. 

Therefore, the answer should be AC+BC.
7 0
3 years ago
How many 3 digit multiples of both 4 and 6 are there?
Daniel [21]

Answer: There 225 3-digit numbers multiple of 4

5 0
3 years ago
Please answer correctly !!!!!!!! Will mark brianliest !!!!!!!!!!!
nexus9112 [7]

Answer:

x=6

Step-by-step explanation:

h(x) = -( x-2)^2 +16

We want when h(x) = 0

0 = -( x-2)^2 +16

Subtract 16 from each side

-16  = -( x-2)^2 +16-16

-16 = -( x-2)^2

Divide by -1

16= ( x-2)^2

Take the square root of each side

±sqrt(16) = sqrt(( x-2)^2 )

±4 = x-2

Add 2 to each sdie

2 ±4 = x-2+2

2+4 = x     2-4 =x

6 =x           -2 =x

since time cannot be negative

x=6

4 0
3 years ago
At 3pm, the length of the shadow of a thin vertical pole standing on level ground is the same as the height of the pole. A while
aliya0001 [1]

Answer: The height of the pole is 175.97 ( approx )

Step-by-step explanation:

Let the height of the pole is x cm,

Also, let the angle of elevation of the sun to the pole at 3 pm is \theta

Thus, by the question,

tan\theta = \frac{\text{ The height of the pole}}{\text{ The height of the shadow}}

\implies tan\theta = \frac{x}{x}    ( at 3pm the height of shadow = height of the pole)

\implies tan\theta = 1

\implies \theta = 45^{\circ}

Again, according to the question,

When the angle of elevation is   (\theta - 12^{\circ}),

The height of shadow = x + 95,

\implies tan(45-12)^{\circ}=\frac{x}{x+95}

\implies tan 33^{\circ}=\frac{x}{x+95}

\implies tan 33^{\circ}x + 95\times tan33^{\circ}=x

\implies tan 33^{\circ}x - x = - 95\times tan33^{\circ}

\implies -0.3505924068 x = - 61.6937213538

x=175.969930202\approx 175.97\text{ cm}

4 0
3 years ago
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