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Elodia [21]
3 years ago
11

When laid flat, a round parachute has a diameter of 10 yards. What is the parachute's radius?

Mathematics
1 answer:
GenaCL600 [577]3 years ago
6 0
Radius is have of diameter so it is 5
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#82 will give brainliest to best answer!​
Fofino [41]

Answer:

\frac{6}{k-6}

Step-by-step explanation:

First, we can factor all of the following equations to turn that weird, huge looking thing into \frac{(k+6)(k-6)}{(k-6)(k-10)} ÷ \frac{(k-6)^2}{k(k-6)} × \frac{6(k-10)}{k(k + 6)}. We know that division is simply multiplication by the reciprocal, so that whole equation will turn into \frac{(k+6)(k-6)}{(k-6)(k-10)} × \frac{k(k-6)}{(k-6)^2} × \frac{6(k-10)}{k(k+6)}. Now we can cancel out some values if they are both in the numerator and denominator, which will turn that still huge looking thing into \frac{6}{k-6} which is our final answer, as it cannot be simplified further.

Hope this helped! :)

7 0
2 years ago
Read 2 more answers
I NEED HELPPP AHHHHHH!!!!!!!!!!!!!!!!!!!!!!!!
Tju [1.3M]
5. complementary = 80 degrees
supplementary = 170 degrees

6. complementary = 47.5 degrees
supplementary = 137.5 degrees

7. complementary = 10 degrees
supplementary = 100 degrees

8. false
9. true
10. true
11. true
12. false
13. true
14. false
6 0
3 years ago
Read 2 more answers
A right cylinder has a radius of 3 and a height of 12. What is its surface area?
Len [333]

Answer:

90π units²

Step-by-step explanation:

(refer to attached)

Total Surface are off a right cylinder = area of its ends + area of curved surface

Given radius, r = 3 units and height, h = 12 units

Area of 2 ends,

= Area of 2 circles

= 2 x πr²

= 2π (3²)

= 2π (9)

=18π units²

Area of curved surface,

= 2πrh

= 2π(3)(12)

= 72π units²

Hence,

Surface area = 18π + 72π = 90π units²

3 0
4 years ago
6^7/6^5 in index form<br>help me
brilliants [131]

Answer:

12^12

Step-by-step explanation:

can u please help me

7 0
3 years ago
PLEASE HELP!!! Use addition to solve the linear system of equations. Include all of your work in your final answer. 2x + y = 5,
Arturiano [62]
I: 2x+y=5
II:3x+2y=4

start by eliminating y

-2*I: -4x-2y=-10
II: 3x+2y=4

add both equations together

-2*I+II: -4x-2y+3x+2y=-10+4
-1x=-6
x=6

insert x=6 into I:
2*6+y=5
y=5-12
y=-7

so the solution is x=6, y=-7
4 0
4 years ago
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