6.70 for paint brushes. for 2 is 6.70×2=$13.40
35-13.40=$21.60 left after 2 paint brushes
4.80×4=$19.20 for 4 tubes of paint
21.60-19.20=$2.40 left after 4 tubes of paint and 2 paint brushes
The graph is not a direct variation because the line does not go through the origin; option C.
<h3>What is a direct variation?</h3>
A direct variation is a relationship between two or more quantities in which as one quantity increases, the other quantity also increases. Similarly, if the other quantity decreases, the other decreases as well.
For the graph of a direct variation, the line must pass through the origin.
Therefore, the graph does not represent a direct variation because the line does not go through the origin.
In conclusion, direct variation involves a corresponding increase or decrease in two related quantities.
Learn more about direct variation at: brainly.com/question/2633726
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Answer:
y = x + 5: x=y−5
2x + y = 17
: x=-1/2y+17/2
Step-by-step explanation:
I do not exactly know what you were asking but I just answered the questions, if that is not what you were looking for tell me so I can try and edit my answer
Answer:
2
Step-by-step explanation:
Answer:
(a)77.4bpm
(b)Mean of Sample 1 = 70.3 beats per minute.
Mean pulse of sample 2 = 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.
Step-by-step explanation:
(a)Population mean pulse.
The pulse of the nine students which represent the population are:
- Perpectual Bempah 64
- Megan Brooks 77
- Jeff Honeycutt 89
- Clarice Jefferson 69
- Crystal Kurtenbach 89
- Janette Lantka 65
- Kevin McCarthy 88
- Tammy Ohm 69
- Kathy Wojdya 87

The population mean pulse is approximately 77.4 beats per minute.
(b)Sample 1: {Janette,Clarice,Megan}
- Janette: 65bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 1

Sample 2: {Janette,Clarice,Megan}
- Perpetual: 64bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 2

The mean pulse of sample 1 is approximately 70.3 beats per minute.
The mean pulse of sample 2 is approximately 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.