The student should compute 6*180 = 1080 because of the formula
S = 180(n-2)
We have n = 8 sides which leads the n-2 part to become n-2 = 8-2 = 6
A circle can be circumscribed about a quadrilateral if and only if the opposite angles of the quadrilater sum up to 180.
This is not the case, so you can't circumscribe a circle about the quadrilateral.
Finding common denominators allows you to more easily get your answer for the problem. fractions are complex as it is if you have a denominator of 16 and 4 your immediate reaction would be to just subtract the process and answer would be completely wrong.
Answer:
c2=a2+b2 1. 172=square +b2 289=225+b2 2.
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