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KiRa [710]
3 years ago
12

1. In a class of 30 students, 5 made A's on the first test. If a student is selected at random to do a

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
6 0

Step-by-step explanation:

State you answer in the simplest form

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Pls help!!!!!!!!!!!!!!!!!!
pochemuha

Answer:

x = 8

Step-by-step explanation:

All sides are equal in terms of symmetry, such as the 5 and 5 opposite the angle 120 that repeats itself at the centre 3 times

6 0
2 years ago
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Find the common difference of the arithmetic sequence –9, -7, -5, ...
MrMuchimi
It’s add positive 2 every time I believe

if I’m wrong I’m so sorry and please tell me I’m wrong for other that have to use this.
If I’m right ya!! XD
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-Pam Pam
3 0
3 years ago
30+30-2 hi brainly people and I
GrogVix [38]

Answer:

58

Step-by-step explanation:

Order of operations.

Additions and subtractions, in the order they appear, from left to right.

30 + 30 - 2 =

= 60 - 2

= 58

5 0
3 years ago
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Anyone know the answer?
Brut [27]
Check out the picture I've got the full explanations on there
Hope it's clear

4 0
3 years ago
There are 5 different pairs of gloves, where left and right are distinguishable. Select 4 of the 10 gloves. (a) How many are the
Shtirlitz [24]

Answer:

(a) How many are there to select 2 pairs of gloves?

10 ways

(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)

130 ways

Step-by-step explanation:

We solve the above questions using Combination

Combination = C(n, r) = nCr

= n!/n! ×(n - r)!

(a) How many are there to select 2 pairs of gloves?

We have 5 pairs of gloves. Therefore, the number of ways to select 2 gloves =5C2

= 5!/2! × (5 - 2)!

= 5!/2! × 3!

= 5 × 4 × 3 × 2 × 1/(2 × 1) × (3 × 2 × 1)!

= 10 ways.

(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)

We are told to select 4 gloves out of the 10 gloves = 10C4

We have 5 pairs, we need to make sure that two out of the selected 4 make a pair = 5 × 2⁴

= 80

Hence,

10C4 - 5C4

= [10!/4! × (10 - 4)!] - 80

= 210 - 80

= 130 ways

3 0
3 years ago
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