Help me with this question

In winter, the price of apples suddenly went up by$0.75 per pound. Sam bought 3 pounds of apples at the new price for a total of

White raven [17]

From the information given, the original price per pound was increased by $ 0.75
Let the original price be x, so the new price is x + 0.75

Sam bought 3 pounds of apples at new price and it cost him 5.88

so we form an equation:

3 (x + 0.75) = 5.88

3x + 2.25 = 5.88

3x = 5.88 - 2.25

3x = 3.63

x = 3.63 / 3

x = 1.21

Therefore the original price per pound is 1.21 dollars

4 0

2 years ago

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HELPPP PLSSS 18. A triangle has verticesA(4,3), B(6,9) and C(2, -3). The triangle is rotated 90°

Mariulka [41]

Answer:

F and H are NOT true

Step-by-step explanation:

Rotation 90° CCW is represented by the transformation ...

(x, y) ⇒ (-y, x)

Then the rotated coordinates are ...

A(4, 3) ⇒ A'(-3, 4) . . . . . quadrant II

B(6, 9) ⇒ B'(-9, 6) . . . . . quadrant II

C(2, -3) ⇒ C'(3, 2) . . . . . quadrant I

The rotated figure will be congruent to the original, because rotation is a rigid transformation.

__

Consider the answer choices:

F: (-3, -4) is A' --- NOT true

G: triangles are congruent --- true

H: B is in quadrant III --- NOT true

J: (3, 2) is the coordinates of C' --- true

Both choices F and H are NOT true.

8 0

2 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$