Answer:
7/3
Step-by-step explanation:
The distances have the ratio ...
(Q -P) = (2/3)(R -P)
Q = P +(2/3)R -(2/3)P = (2R +P)/3
Qy = (2Ry +Py)/3 = (2·0 +7)/3 = 7/3
, 4, 2)to the xy............................................
If the areas of two equilateral triangles are 27 yd² and 75 yd², then the ratio of these areas is 27/75 = 9/25
If the ratios of the areas are 9:25, then their similarity ratio and the ratio of their perimeters is √9:√35 = 3:5.
3 : 5; 3 : 5 <==ANSWER
You have to subtract the largest number from the smallest and you get your range. Which would be 7.5-2.1 equals 5.4 which is b.