Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
The dependent variable is the data we collect during the experiment. This data is collected as a result of changing the independent variable.
Answer: 300 grams
If Anna’s doctor recommends getting 60% of her calories from carbohydrates, it means that (2000*.60) or 1200 calories should come from carbohydrates.
<span>If one gram of carbohydrate provides 4 calories of energy, then 1200 calories is equal to (1200/4) or 300 grams of carbohydrates Anna should consume each day.</span>
Here is the answer that would best complete the given statement above. Biotechnology raises ethical questions, primarily concerning the <span>ways in which knowledge should be used. Hope this is the answer that you are looking for. Have a great day!</span>
