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2 years ago

The point (4, -3) is on the graph of which function

Mathematics

1 answer:

Kazeer [188]2 years ago

3 0

Replace x and Y in the answers and see which one works:

A) 4(4) -3 = 16-3 = 13, not -3 FALSE.

B) 1/2(4) - 5 = 2-5 = -3 TRUE

The correct answer is B

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2. In the triangle below, NE and KL are perpendicular bisectors. Knowing that the sum of interior angles in

Stells [14]

Answer:

a = 60°

Step-by-step explanation:

From the picture attached,

In the given triangle,

NE and ML are the perpendicular bisectors of two sides of the triangle.

Therefore, m∠MEK = m∠MLK = 90°

Since, sum of interior angles of polygon KLME = 360°

m∠MEK + m∠MLK + m∠EML + m∠EKL = 360°

90° + 90° + 120° + a = 360°

a = 360° - 300°

a = 60°

5 0

2 years ago

Find the slope of the line through the points (6,16) and (−6,4)

MakcuM [25]

$m = \frac{y2-y1}{x2-x1}$

$m = \frac{4-16}{-6-6} \\m = \frac{-12}{-12} \\\\m = 1$

Therefore, the slope of the line is 1. In case if you want to know the equation.

$y=mx+b\\y=x+b\\4=-6+b\\4+6=b\\10=b\\$

Therefore, the equation is y=x+10 by substituting the (-6,4) or we can substitute (6,16) too.

$y=mx+b\\y=x+b\\16=6+b\\16-6=b\\10=b\\$

It's the same, you can use any orders given.

Overall, the slope is 1 and the equation is y=x+10

3 0

2 years ago

Your boss tells you that she knows the length of the widgets your company makes is normally distributed with a mean of 25 inches

sp2606 [1]

Answer:

Mean of sampling distribution = 25 inches

Standard deviation of sampling distribution = 4 inches

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 25 inches

Standard Deviation, σ = 12 inches

Sample size, n = 9

We are given that the distribution of length of the widgets is a bell shaped distribution that is a normal distribution.

a) Mean of the sampling distribution

The best approximator for the mean of the sampling distribution is the population mean itself.

Thus, we can write:

$\bar{x} = \mu = 25\text{ inches}$

b) Standard deviation of the sampling distribution

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{12}{\sqrt{9}} = 4\text{ inches}$

8 0

2 years ago

What is the horizontal asympote of this graph?

Anna35 [415]

Using it's concept, it is found that the graph has no horizontal asymptote.

<h3>What are the horizontal asymptotes of a function f(x)?</h3>

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, we have that:

The function is undefined for x < 0, hence $\lim_{x \rightarrow -\infty} f(x)$ is undefined.

For x > 0, the funciton goes to infinity, hence $\lim_{x \rightarrow \infty} f(x) = \infty$ .

Thus, the graph has no horizontal asymptote.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

4 0

2 years ago

Verify that each equation is an identity.<br><br> Show Work plzz!!

Pavlova-9 [17]

Answer:

Step-by-step explanation:

sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x

$\frac{cos^2x}{cos^2x}$ = 1

3 0

2 years ago