Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
Answer:
3
Step-by-step explanation:
4 1/2 + 3 1/3 + 2 + 2 1/6
= 4 3/6 + 3 2/6 + 2 + 2 1/6
= 4 + 3 + 2 + 2 + 3/6 + 2/6 + 1/6
= 11 + 6/6
= 11 + 1
= 12
There are 4 numbers, therefore average = 12 ÷ 4 = 3
Answer:
Step-by-step explanation:
im pretty sure its a
I believe you would just divide 134 by 8
134/8 = 16.75
That means you would earn $16.75 per hour.
Answer:
Y <= 1
Step-by-step explanation:
This is because it is a solid line and a filled point on the top line, the bottom line is irrelevant for this question
