How to find the median of a rhombus

1 answer:

8 0

You get the top of the rhombus and the bottom and then add it. The answer you get you have to divide it by 2 to get your answer! (I am so sorry if I got this wrong. I am new so...)

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I dont know how to find x

Verdich [7]

Simplify both sides:

x
—- = -9
4

now isolate the variable (x):

x= -9 • 4
x= -36

4 0

3 years ago

Find the dimensions of a rectangle whose area is 208 cm2 and whose perimeter is 58 cm

Mrrafil [7]

Answer:

13cm× 16cm

Step-by-step explanation:

Please see attached picture for full solution.

3 0

3 years ago

Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half

BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

$P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}$

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

$P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091$