Given:
n = 27, sample size
df = n-1 = 26, degrees of freedom
xb = 11.8, sample mean
s = 2.3, sample standard deviation.
Because population statistics are not known, we should use the Student's t-distribution.
At 99% confidence interval, the t-value = 2.779 (from tables).
The confidence interval is
11.8 +/- 2.779*(2.3/√(27)) = 11.8 +/- 1.23 = (10.57, 13.03)
Answer: (10.6, 13.0) to the nearest tenth
24. 1.00000000
25. 2.9678900522
26. 1.1950500000000
Tan(35)=ck/cd
0.7= ck/3
ck=2.1
Tan(65)=cj/cd
2.1=cj/3
cj=6.3
jk=6.3-2.1=4.2
Answer:
i) The approximate solutions are: 
, 
.
ii) The approximate solutions are: 
, 
.
Step-by-step explanation:
i) The best approach to estimate graphically the solution of 
is graphing the following system of equations:
(1)
(2)
And labeling the points in which both intersects each other. We include the result in the image 'solution-i'. The approximate solutions are: , .
ii) The best approach to estimate graphically the solution of 
is graphing the following system of equations:
(1)
(2)
And labeling the points in which both intersects each other. We include the result in the image 'solution-ii'. The approximate solutions are: , .
Answer:
<u>Easy way to distinguish:</u>
- Linear function forms a AP and exponential function forms a GP
<u>We see f(x) is series of:</u>
- This is a AP with common difference of 6 and the first term of 8
<u>g(x) is series of:</u>
- 4, 12, 36, 108, 324
- This is a GP with common ratio of 3 and the first term of 4
1. <u>g(x) is exponential function:</u>
2. <u>f(x) is linear function:</u>
