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liberstina [14]
4 years ago
12

If 97 of 200 is 100% then how much of 200 is 112%

Mathematics
1 answer:
pickupchik [31]4 years ago
3 0
To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 112 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 112 is 100%, so we can write it down as 112=100%.
4. We know, that x is 200% of the output value, so we can write it down as x=200%.
5. Now we have two simple equations:
1) 112=100%
2) x=200%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
112/x=100%/200%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 200% of 112

112/x=100/200
(112/x)*x=(100/200)*x - we multiply both sides of the equation by x
112=0.5*x - we divide both sides of the equation by (0.5) to get x
112/0.5=x
224=x
x=224

now we have:
200% of 112=224



●I tried my best I was never good with percentages my least favorite.... Please let me know if you got it wrong. If you do I'm sorry.
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Answer:

x = 1.2

Step-by-step explanation:

AD/AB = DE/BC (Similarity Theorem)

AD = 6 + 4 = 10

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Plug in the values

10/6 = 2/x

Cross multiply

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8 0
3 years ago
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

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Answer: (5, -2)

Step-by-step explanation:

y= x-7\\2x+y=8

Substitute x-7 for y in 2nd equation

2x+ x-7 =8\\3x-7=8\\3x = 15\\x=5

Solve for y

y=5-7\\y=-2

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kykrilka [37]

Answer:

f(x) = (x^2 -4) ( x-5)

Here quadratic factor is ( x^2 -4) As x contains power 2

and linear factor is (x-5) as x contains power 1

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