The answer to the question
5x^2-3x^2= 2x^2
2x^2-14
2(x^2-7)
Formula= (y2-y1)/ (x2-x1)
(-5 - -1) / (-2 - -4)
(-4) / (2) = -2
q8 is C
(-3 - -3) / (8 - 4)
(0) / (4) = 0
q12 is D
Answer:
Step-by-step explanation:
Finding max/min: There are two ways to find the absolute maximum/minimum value for f(x) = ax2 + bx + c: Put the quadratic in standard form f(x) = a(x − h)2 + k, and the absolute maximum/minimum value is k and it occurs at x = h. If a > 0, then the parabola opens up, and it is a minimum functional value of f.
Answer:
28p^2+22p-30
Step-by-step explanation:
I'm a genius
