Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
Answer:
1) 180 degrees; straight angle
2) (5x-18)+(4x+45)=108
3) x=17
4) 90 degrees; right angle
5) (3x+6)+(5x+4)=90
6)x=10
Step-by-step explanation:
Answer:
41,300
you can take the 4.13 and put it in the first three spaces hope this helps
Start with the 3 then move on
What type of transformation are you interested in? Please be specific.
If you begin with f(x) = x^2 and then translate its graph 2 units to the right, then the new function will be g(x) = (x-2)^2. That's for starters.