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Sladkaya [172]
3 years ago
13

a mechanic buys $14.56 worth of parts from a supplier. if he pays for the parts with a $20 bill, how much change will he receive

?
Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0
The corecct answer is 5.44
Bond [772]3 years ago
3 0
He will receive $5.04
You might be interested in
length of a rectangle is 4 inches less than its width, and its perimeter is 24 inches. Which of the following systems of equatio
Anestetic [448]

Answer:

length= 8 width = 4

Step-by-step explanation:

24-8=16

16/2=8

8+8+4+4=16+8=24

4 0
3 years ago
What is the measure of the missing angle?)<br><br>Please explain how u got the answer so I can learn
anygoal [31]

Step-by-step explanation:

let x be the another angle

so

x+40=90

x=90-40

x=50

The measure of missing angle is 50

hope it helps

7 0
3 years ago
Read 2 more answers
Can someone help solve this problem??
Shtirlitz [24]

Answer:

the answer is 22

Step-by-step explanation:

-|-7|+|-2+17

the 7 becomes positive

(7|+|-2)+17

5+17

=22

7 0
3 years ago
Read 2 more answers
Monique bought a shirt for $22.80 during a 30% off sale. How much does the shirt cost when it is not on sale?
spin [16.1K]

Answer:

29.64

Step-by-step explanation:

First we multiply 0.3 with 22.8.This will give us 6.84 which is the 30% off.Now we add 22.80 and 6.84 and we will get our answer 29.64.

4 0
2 years ago
Read 2 more answers
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
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