Answer:
It is a perfect cube with sides of 5.
Step-by-step explanation:
If 125 was a perfect square, there would be a whole number A which, squared, would give us 125.

We can see that the roots are not whole numbers.
(Tip: without a calculator, we can find this by testing
to see if any give us 125. We get 100, 121, 144 respectively. None of them is 125.)
If it was a perfect cube, there would be a whole number B which, cubed, would give us 125.
![B^3 = 125\\B = \sqrt[3]{125} \\B = 5](https://tex.z-dn.net/?f=B%5E3%20%3D%20125%5C%5CB%20%3D%20%5Csqrt%5B3%5D%7B125%7D%20%5C%5CB%20%3D%205)
As we can see, there IS a whole number B: 5 !
(Without a calculator, like the previous one, we could try
and we'd find that
= 125)
Answer: It is a perfect cube with sides of 5.