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Aleonysh [2.5K]
3 years ago
6

Shrina is selling cookie dough for her soccer team. She sold 2 tubs of

Mathematics
1 answer:
Inga [223]3 years ago
6 0

Answer: 22

Step-by-step explanation:

She sold two tubs of Oatmeal Raisins and it's 6 dollars a tub so we can do 6*2 or 6+6 (doesn't matter). We get $12. Then, she also sells 2 tubs of Peanut Butter, and since it's $5 a tub, then we do 5*2 or 5+5 to get 10. We add 12 and 10 (12+10) and get 22.

I'm not sure if this is right because you added $22, $24, $20, and $11 and I'm not sure what the purposes of those are.

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Carl, Gilda, Conroy, and Kyla are the four candidates in a school election. Carl received 1/5 of the votes, Gilda received 5% of
Juliette [100K]
Firstly, we can convert all of the fractions into percentages. To do this, we need to make the denominator of the fraction 100, and whatever we do to the denominator we must also do to the numerator.

5 x 20 = 100
1 x 20 = 20.

So Carl recieves 20/100 or 20% of the votes.

4 x 25 = 100
1 x 15 = 25

So Conroy receives 25/100 or 25% of the votes.

If we add these together and Gilda's 5%, we get 50%. Since there are 100% votes overall, we need to do 100 - 50 = 50.
 
Kyla receives 50% of the votes.
8 0
3 years ago
Read 2 more answers
27 girls and 18 boys i need same ratio of girls and boys on each team please
otez555 [7]
The ratio is 3:2, hope it helps
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A student took a total of 4 tests over the course of 8 weeks. How many weeks of school will the student attend to take a total o
Julli [10]

Answer:

4/8 = 20/x

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3 0
3 years ago
A pack of 8 batteries cost 4.72!What is cost per battery?
Mrrafil [7]
4.72 x 1 = 4.72
8 x X =8x
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8 0
2 years ago
Write an equation for the hyperbola with vertices (-7,0) and (7,0), conjugate axis of length of 10?
lina2011 [118]
The hyperbola is more or less as in the picture below

notice the traverse axis is horizontal, meaning the positive fraction will be the one with the "x" variable in it, and notice the length of the "a" component

the conjugate axis is 10, notice the length of the  "b" component

thus    \bf \textit{hyperbola with horizontal traverse axis }\\\\
\cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})

so, hmmmm plug in those values

6 0
3 years ago
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