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andreev551 [17]

3 years ago

7

Solve for "x"4x-(2x 3)=7

1 answer:

IRISSAK [1]3 years ago

3 0

4x-(2x 3) = 7

4x-6x = 7

-2x = 7

x = -7/2

x = -3.5

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JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.

anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

$JL = 48$

$KM = 20$

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

$P = 2\sqrt{(JL)^2 + (KM)^2}$

Substitute values for JL and KM

$P = 2\sqrt{48^2 + 20^2}$

$P = 2\sqrt{2304 +400}$

$P = 2\sqrt{2704}$

$P = 2 * 52$

$P = 104$

<em>Hence, the perimeter is 104 units</em>

5 0

2 years ago

Solve for x:<br> 1 1/5x−2 1/3<1/7x+1 1/2

Mashcka [7]

Answer: $x$

Step-by-step explanation:

$1\frac{1}{5}x-2\frac{1}{3}$

Add $2\frac{1}{3}$ on both sides and subtract $\frac{1}{7}x$ on both sides to leave x's on the left side and independent values on the right.

$(2\frac{1}{3}-\frac{1}{7}x) +1\frac{1}{5}x-2\frac{1}{3}$

$1\frac{1}{5}x-\frac{1}{7}x$

Solve the fractions.

$1(\frac{1}{5}-\frac{1}{7})x$

$1(\frac{(1)(7)-(5)(1)}{(5)(7)} )x$

$1(\frac{7-5}{35} )x$

$1(\frac{2}{35} )x$

$1\frac{2}{35}x$

Convert the mixed fraction $1\frac{2}{35}$ to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.

$\frac{37}{35}x$

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.

$(\frac{35}{37}) (\frac{37}{35})x$

$x$

$x$

$x$

5 0

3 years ago

A students work to solve 2 6/7 / 2/7 is shown below.

Alexus [3.1K]

A) the only mistake is changing the mixed number to an improper fraction .

6 0

2 years ago

Read 2 more answers

Is 3(b+c) equivalent expressions?<br><br>A. True <br><br>B. False

andre [41]

Answer:

Is 3(b+c) equivalent expressions?

A. True

8 0

2 years ago

Read 2 more answers

What is the slope of the line graphed in the coordinate grid?

zvonat [6]

Answer:

3/4

Step-by-step explanation:

I drew a slope triangle and found the slope by finding the distance between two points on the line.

$vertical distance/horizontal distance$

Hope this helped!

5 0

2 years ago