Answer: for number 7
Step-by-step explanation:
a²+b²=c²
3²+8²=c²
9+64=c²
What is the completely factored form of 12xy – 9x – 8y + 6? (3x – 2)(4y – 3) 3x(4y – 3) – 2(4y + 3) –6x(4y – 3)(4y – 3) (3x – 2)
2 answers:
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
We just need to find the factors of the polynomial with two variables.
1) Taking the common factor from first two terms i.e. 3x
So, it becomes,
2) Now, taking the common factor from last two terms i.e. -2
So, it becomes,
So, Combined form will be given as
Hence, First option is correct.
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Answer:
Step-by-step explanation:
To copy an angle we follow the following steps,
1). Draw a working line with the help of a straightedge.
2). Now we put a point S as the vertex of the angle.
3). Construct an arc with a radius 'r' (any length ) from vertex S which intersects the working line say at V.
4). With the same radius we draw an arc from point E which intersects the line ED and EF at G and H respectively.
5). Mark an arc from point G which intersects line EF at I.
6). Measure the distance between points G and I with compass and mark an arc from point V which intersects the previous arc say at U.
7). Now join the points S and U.
Hence we copy any angle.
The given function is
f(x) = x - ln(8x), on the interval [1/2, 2].
The derivative of f is
f'(x) = 1 - 1/x
The second derivative is
f''(x) = 1/x²
A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0 => 1/x = 1 => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079
The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2) = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.
Answer:
Minimum value = 1 - ln(8)
Maximum value = 2 - ln(16)
f(x) = x - ln(8x), on the interval [1/2, 2].
The derivative of f is
f'(x) = 1 - 1/x
The second derivative is
f''(x) = 1/x²
A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0 => 1/x = 1 => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079
The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2) = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.
Answer:
Minimum value = 1 - ln(8)
Maximum value = 2 - ln(16)