Answer:
EF² = FA²+ EA²
20² = 12² + FA²
400 -144 = FA²
256 =FA²
16cm = FA
Now in Δ DAG
DG² = AG² + DA²
13² = 12 ²+ DA²
169 -144 = DA²
25 = DA²
5cm = DA
Then that means diagonal DF = DA + FA
= 5 + 16
= 21cm
Step-by-step explanation:
The answer is 2.6 hours
To solve you just do 1.5 % 115, which gives you the amount of time per mile, then you use the outcome of the division to multiply by 200 to get 2.6
Answer:
the answer to that is B hope it helps
Assume that the incline is frictionless.
Refer to the diagram shown below.
Note that 75 cm = 0.75 m.
Therefore the angle of the incline is given by
sin(x) = 0.75/2.3 = 0.3261.
The weight pushed up the incline is W = 5501 N.
The component of the weight acting down the incline is
W*sin(x) = 5501*0.3261 = 1793.9 N
The force, F, should overcome this weight acting along the incline, therefore
F = 1794 N (nearest integer)
Answer: 1794 N
The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers
two consecutive even integers: n, n+2
next two consecutive even integers n+4, n+6
n+(n+2) >= 7+1/2(n+4 +n+6)
combine like terms
2n+2 >= 7 +1/2(2n+10)
distribute 1/2
2n+2 >= 7+n+5
2n+2>= n+12
subtract n from each side
n+2>= 12
subtract 2 from each side
n>10
4 integers : 10, 12 ,14, 16