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lina2011 [118]
2 years ago
12

The formula below gives l, the interest earned by depositing p dollars in a bank account at annual interest rate r for one year.

Mathematics
1 answer:
shtirl [24]2 years ago
4 0
C. p=75/r
......................
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8. If you choose from the following M&M colors, what is the probability
astraxan [27]

Answer:

8/26

Step-by-step explanation:

there are 8 blue out of a total of 26 in total

3 0
3 years ago
Find the equation of a line passing through (3, -5) that is parallel to 2x+6y=10
Zina [86]

Answer:

The equation of the line would be y = -1/3x - 4

Step-by-step explanation:

In order to find this, we first need to find the slope of the original line. We do this by solving for y.

2x + 6y = 10

6y = -2x + 10

y = -1/3x + 5/3

Now that we see the slope as -1/3, we know the new line will have the same slope thanks to the definition of parallel lines. So, we can use this slope and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - -5 = -1/3(x - 3)

y + 5 = -1/3x + 1

y = -1/3x - 4

4 0
3 years ago
Given matrices S and T below, which statement is true?
harina [27]
The matrices are
S =(4 11                           T= ( -8 11
      -3  -8)                                 3  4 )
Inverse of a matrix is a matrix derived from another matrix such that if you pre- multiply it with the original matrix you get a unit matrix.
if we multiply S and T
 ST will be 
        ( 4 11    ×      (-8 11   = ( 1 0
          -3 -8)           -3 -4)         0 1)
and also TS
          ( -8 11      ×     (4 11  = ( 1 0
             -3 -4)            -3 -8)       0 1)
therefore, matrices S and T are inverses of each other because ST = TS= I 



.
8 0
3 years ago
Read 2 more answers
Need help please.........................
Archy [21]

Answer:

16t^{2} + 2t - 6

Step-by-step explanation:

(12t^{2}  + 5t -y) - (-4t^{2} + 3t -1)

simplify

12t^{2} + 5t -7 +4t^{2} -3t +1

combine like terms

16t^{2} + 2t - 6

8 0
2 years ago
Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

3 0
3 years ago
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